Boynton Beach vs Flagstaff Crime Comparison
Is Boynton Beach or Flagstaff Safer?
Flagstaff is the safer city, with a total crime rate 0% lower than Boynton Beach based on 2024 FBI data. Boynton Beach has higher rates in 3 of 7 crime categories.
The biggest difference is in murder, where Boynton Beach has a 44% lower rate.
Boynton Beach, FL
Safety Score
50/100
Population
81,473
Total Crime Rate
2,702.7
Category Wins
3/7
Flagstaff, AZ
Safety Score
50/100
Population
76,433
Total Crime Rate
2,697.8
Category Wins
4/7
Detailed Crime Rate Comparison
| Crime Type | Boynton Beach | Flagstaff | Difference |
|---|---|---|---|
| Total Crime Rate | 2,702.7 | 2,697.8 | +4.9 |
| Violent Crime Rate | 419.8 | 465.8 | -46.0 |
| Murder Rate | 3.7 | 6.5 | -2.9 |
| Rape Rate | 36.8 | 70.7 | -33.8 |
| Robbery Rate | 77.3 | 53.6 | +23.7 |
| Aggravated Assault Rate | 299.5 | 332.3 | -32.8 |
| Property Crime Rate | 2,283.0 | 2,232.0 | +50.9 |
| Burglary Rate | 203.8 | 123.0 | +80.8 |
| Larceny-Theft Rate | 1,982.3 | 1,970.4 | +11.9 |
| Motor Vehicle Theft Rate | 97.0 | 138.7 | -41.7 |
All rates per 100,000 residents. Source: FBI UCR 2024.
Frequently Asked Questions
Is Boynton Beach or Flagstaff safer?
Flagstaff is safer with a total crime rate of 2,698 per 100K vs 2,703 for Boynton Beach — a 0% difference.
How do violent crime rates compare?
Boynton Beach has a violent crime rate of 419.8 per 100K while Flagstaff has 465.8. Boynton Beach has lower violent crime.